Base | Representation |
---|---|
bin | 10011010111110011000… |
… | …001010110100000101100 |
3 | 11201021010011021002111210 |
4 | 103113303001112200230 |
5 | 133302320330043200 |
6 | 2455315513514420 |
7 | 165114632153013 |
oct | 23276301264054 |
9 | 4637104232453 |
10 | 1331222112300 |
11 | 4736281a5293 |
12 | 195bbb712a10 |
13 | 986c27266c2 |
14 | 4860803ba7a |
15 | 24964ea6650 |
hex | 135f305682c |
1331222112300 has 144 divisors (see below), whose sum is σ = 4076791846400. Its totient is φ = 334450425600.
The previous prime is 1331222112293. The next prime is 1331222112347. The reversal of 1331222112300 is 32112221331.
It is a super-3 number, since 3×13312221123003 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 386541 + ... + 1676859.
Almost surely, 21331222112300 is an apocalyptic number.
1331222112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1331222112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2038395923200).
1331222112300 is an abundant number, since it is smaller than the sum of its proper divisors (2745569734100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1331222112300 is a wasteful number, since it uses less digits than its factorization.
1331222112300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1290536 (or 1290529 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1331222112300 its reverse (32112221331), we get a palindrome (1363334333631).
It can be divided in two parts, 133122 and 2112300, that added together give a palindrome (2245422).
The spelling of 1331222112300 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-two million, one hundred twelve thousand, three hundred".
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