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1331222112300 = 22352191811290319
BaseRepresentation
bin10011010111110011000…
…001010110100000101100
311201021010011021002111210
4103113303001112200230
5133302320330043200
62455315513514420
7165114632153013
oct23276301264054
94637104232453
101331222112300
114736281a5293
12195bbb712a10
13986c27266c2
144860803ba7a
1524964ea6650
hex135f305682c

1331222112300 has 144 divisors (see below), whose sum is σ = 4076791846400. Its totient is φ = 334450425600.

The previous prime is 1331222112293. The next prime is 1331222112347. The reversal of 1331222112300 is 32112221331.

It is a super-3 number, since 3×13312221123003 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 386541 + ... + 1676859.

Almost surely, 21331222112300 is an apocalyptic number.

1331222112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1331222112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2038395923200).

1331222112300 is an abundant number, since it is smaller than the sum of its proper divisors (2745569734100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331222112300 is a wasteful number, since it uses less digits than its factorization.

1331222112300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1290536 (or 1290529 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1331222112300 its reverse (32112221331), we get a palindrome (1363334333631).

It can be divided in two parts, 133122 and 2112300, that added together give a palindrome (2245422).

The spelling of 1331222112300 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-two million, one hundred twelve thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 19 20 25 30 38 50 57 60 75 76 95 100 114 150 181 190 228 285 300 362 380 475 543 570 724 905 950 1086 1140 1425 1810 1900 2172 2715 2850 3439 3620 4525 5430 5700 6878 9050 10317 10860 13575 13756 17195 18100 20634 27150 34390 41268 51585 54300 68780 85975 103170 171950 206340 257925 343900 515850 1031700 1290319 2580638 3870957 5161276 6451595 7741914 12903190 15483828 19354785 24516061 25806380 32257975 38709570 49032122 64515950 73548183 77419140 96773925 98064244 122580305 129031900 147096366 193547850 233547739 245160610 294192732 367740915 387095700 467095478 490321220 612901525 700643217 735481830 934190956 1167738695 1225803050 1401286434 1470963660 1838704575 2335477390 2451606100 2802572868 3503216085 3677409150 4437407041 4670954780 5838693475 7006432170 7354818300 8874814082 11677386950 13312221123 14012864340 17516080425 17749628164 22187035205 23354773900 26624442246 35032160850 44374070410 53248884492 66561105615 70064321700 88748140820 110935176025 133122211230 221870352050 266244422460 332805528075 443740704100 665611056150 1331222112300