13312241300111 has 4 divisors (see below), whose sum is σ = 14336259861672. Its totient is φ = 12288222738552.

The previous prime is 13312241300053. The next prime is 13312241300191. The reversal of 13312241300111 is 11100314221331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13312241300111 - 2²⁶ = 13312174191247 is a prime.

It is a super-2 number, since 2×13312241300111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13312241300191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512009280761 + ... + 512009280786.

It is an arithmetic number, because the mean of its divisors is an integer number (3584064965418).

Almost surely, 2^{13312241300111} is an apocalyptic number.

13312241300111 is a deficient number, since it is larger than the sum of its proper divisors (1024018561561).

13312241300111 is a wasteful number, since it uses less digits than its factorization.

13312241300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1024018561560.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13312241300111 its reverse (11100314221331), we get a palindrome (24412555521442).

The spelling of 13312241300111 in words is "thirteen trillion, three hundred twelve billion, two hundred forty-one million, three hundred thousand, one hundred eleven".