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1331230013021 is a prime number
BaseRepresentation
bin10011010111110011011…
…111011111011001011101
311201021010201010111021002
4103113303133133121131
5133302324340404041
62455320355120045
7165115056260126
oct23276337373135
94637121114232
101331230013021
11473631701207
121960022a3025
13986c426189c
14486090d704d
1524965a1759b
hex135f37df65d

1331230013021 has 2 divisors, whose sum is σ = 1331230013022. Its totient is φ = 1331230013020.

The previous prime is 1331230013011. The next prime is 1331230013023. The reversal of 1331230013021 is 1203100321331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1237189044100 + 94040968921 = 1112290^2 + 306661^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331230013021 - 234 = 1314050143837 is a prime.

Together with 1331230013023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331230012984 and 1331230013002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1331230013023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665615006510 + 665615006511.

It is an arithmetic number, because the mean of its divisors is an integer number (665615006511).

Almost surely, 21331230013021 is an apocalyptic number.

It is an amenable number.

1331230013021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331230013021 is an equidigital number, since it uses as much as digits as its factorization.

1331230013021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1331230013021 its reverse (1203100321331), we get a palindrome (2534330334352).

The spelling of 1331230013021 in words is "one trillion, three hundred thirty-one billion, two hundred thirty million, thirteen thousand, twenty-one".