1331240161133 has 4 divisors (see below), whose sum is σ = 1331914892028. Its totient is φ = 1330565430240.

The previous prime is 1331240161123. The next prime is 1331240161171. The reversal of 1331240161133 is 3311610421331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 100766883844 + 1230473277289 = 317438^2 + 1109267^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331240161133 - 2¹⁰ = 1331240160109 is a prime.

It is a super-2 number, since 2×1331240161133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1331240161096 and 1331240161105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331240161123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337362488 + ... + 337366433.

It is an arithmetic number, because the mean of its divisors is an integer number (332978723007).

Almost surely, 2^{1331240161133} is an apocalyptic number.

It is an amenable number.

1331240161133 is a deficient number, since it is larger than the sum of its proper divisors (674730895).

1331240161133 is an equidigital number, since it uses as much as digits as its factorization.

1331240161133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 674730894.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 1331240161133 its reverse (3311610421331), we get a palindrome (4642850582464).

The spelling of 1331240161133 in words is "one trillion, three hundred thirty-one billion, two hundred forty million, one hundred sixty-one thousand, one hundred thirty-three".