133130031141040 has 40 divisors (see below), whose sum is σ = 309527984097360. Its totient is φ = 53251898616576.

The previous prime is 133130031141001. The next prime is 133130031141049. The reversal of 133130031141040 is 40141130031331.

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-3 number, since 3×133130031141040³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 133130031140996 and 133130031141014.

It is not an unprimeable number, because it can be changed into a prime (133130031141049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42824451 + ... + 45827869.

It is an arithmetic number, because the mean of its divisors is an integer number (7738199602434).

Almost surely, 2^{133130031141040} is an apocalyptic number.

133130031141040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133130031141040 is an abundant number, since it is smaller than the sum of its proper divisors (176397952956320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133130031141040 is a wasteful number, since it uses less digits than its factorization.

133130031141040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3557509 (or 3557503 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 133130031141040 its reverse (40141130031331), we get a palindrome (173271161172371).

The spelling of 133130031141040 in words is "one hundred thirty-three trillion, one hundred thirty billion, thirty-one million, one hundred forty-one thousand, forty".