Base | Representation |
---|---|
bin | 10011010111111000100… |
… | …001100001010000100100 |
3 | 11201021100120222100222100 |
4 | 103113320201201100210 |
5 | 133303012443243022 |
6 | 2455333012332100 |
7 | 165120132643536 |
oct | 23277041412044 |
9 | 4637316870870 |
10 | 1331314431012 |
11 | 47367531a745 |
12 | 196026614030 |
13 | 987088aab67 |
14 | 486163cd856 |
15 | 2496d1401ac |
hex | 135f8861424 |
1331314431012 has 18 divisors (see below), whose sum is σ = 3365267034038. Its totient is φ = 443771476992.
The previous prime is 1331314430933. The next prime is 1331314431053. The reversal of 1331314431012 is 2101344131331.
1331314431012 is a `hidden beast` number, since 1 + 3 + 31 + 314 + 4 + 310 + 1 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 1120324870116 + 210989560896 = 1058454^2 + 459336^2 .
It is a tau number, because it is divible by the number of its divisors (18).
It is a super-2 number, since 2×13313144310122 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 18490478173 + ... + 18490478244.
Almost surely, 21331314431012 is an apocalyptic number.
1331314431012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1331314431012 is an abundant number, since it is smaller than the sum of its proper divisors (2033952603026).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1331314431012 is a wasteful number, since it uses less digits than its factorization.
1331314431012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36980956427 (or 36980956422 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 1331314431012 its reverse (2101344131331), we get a palindrome (3432658562343).
The spelling of 1331314431012 in words is "one trillion, three hundred thirty-one billion, three hundred fourteen million, four hundred thirty-one thousand, twelve".
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