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133134040143 = 32131137897779
BaseRepresentation
bin111101111111101101…
…0000011110001001111
3110201122100011222110200
41323333122003301033
54140124303241033
6141054432304543
712422120445426
oct1737732036117
9421570158420
10133134040143
1151509770955
12219763a2153
13c72928a760
14662d8042bd
1536e3083013
hex1eff683c4f

133134040143 has 12 divisors (see below), whose sum is σ = 207097395960. Its totient is φ = 81928640016.

The previous prime is 133134040133. The next prime is 133134040181. The reversal of 133134040143 is 341040431331.

It is not a de Polignac number, because 133134040143 - 25 = 133134040111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133134040133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 568948773 + ... + 568949006.

It is an arithmetic number, because the mean of its divisors is an integer number (17258116330).

Almost surely, 2133134040143 is an apocalyptic number.

133134040143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

133134040143 is a deficient number, since it is larger than the sum of its proper divisors (73963355817).

133134040143 is a wasteful number, since it uses less digits than its factorization.

133134040143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1137897798 (or 1137897795 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 133134040143 its reverse (341040431331), we get a palindrome (474174471474).

The spelling of 133134040143 in words is "one hundred thirty-three billion, one hundred thirty-four million, forty thousand, one hundred forty-three".

Divisors: 1 3 9 13 39 117 1137897779 3413693337 10241080011 14792671127 44378013381 133134040143