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133151132302140 = 22352219185538369
BaseRepresentation
bin11110010001100110101001…
…111100010011101100111100
3122110110010100100100222121210
4132101212221330103230330
5114423022004332132030
61151104441415124420
740021565120300331
oct3621465174235474
9573403310328553
10133151132302140
1139476094a3a447
1212b256b8973710
13593b137114cb4
1424c4798d92988
15105d876ed3bb0
hex7919a9f13b3c

133151132302140 has 24 divisors (see below), whose sum is σ = 372823170446160. Its totient is φ = 35506968613888.

The previous prime is 133151132302117. The next prime is 133151132302141. The reversal of 133151132302140 is 41203231151331.

It is a super-3 number, since 3×1331511323021403 (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 133151132302098 and 133151132302107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133151132302141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1109592769125 + ... + 1109592769244.

It is an arithmetic number, because the mean of its divisors is an integer number (15534298768590).

Almost surely, 2133151132302140 is an apocalyptic number.

133151132302140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133151132302140 is an abundant number, since it is smaller than the sum of its proper divisors (239672038144020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133151132302140 is a wasteful number, since it uses less digits than its factorization.

133151132302140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2219185538381 (or 2219185538379 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 133151132302140 its reverse (41203231151331), we get a palindrome (174354363453471).

The spelling of 133151132302140 in words is "one hundred thirty-three trillion, one hundred fifty-one billion, one hundred thirty-two million, three hundred two thousand, one hundred forty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 2219185538369 4438371076738 6657556615107 8876742153476 11095927691845 13315113230214 22191855383690 26630226460428 33287783075535 44383710767380 66575566151070 133151132302140