Base | Representation |
---|---|
bin | 11110010001101010101111… |
… | …000101110101010101000000 |
3 | 122110110112122200122122110222 |
4 | 132101222233011311111000 |
5 | 114423104442443340134 |
6 | 1151110444250442212 |
7 | 40022111521202555 |
oct | 3621525705652500 |
9 | 573415580578428 |
10 | 133155513652544 |
11 | 39477a33110899 |
12 | 12b26520133368 |
13 | 593b684a48426 |
14 | 24c4a92c14a2c |
15 | 105da31986a2e |
hex | 791aaf175540 |
133155513652544 has 14 divisors (see below), whose sum is σ = 264230472404394. Its totient is φ = 66577756826240.
The previous prime is 133155513652531. The next prime is 133155513652589. The reversal of 133155513652544 is 445256315551331.
It can be written as a sum of positive squares in only one way, i.e., 77484217510144 + 55671296142400 = 8802512^2 + 7461320^2 .
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1040277450347 + ... + 1040277450474.
Almost surely, 2133155513652544 is an apocalyptic number.
It is an amenable number.
133155513652544 is a deficient number, since it is larger than the sum of its proper divisors (131074958751850).
133155513652544 is an equidigital number, since it uses as much as digits as its factorization.
133155513652544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2080554900833 (or 2080554900823 counting only the distinct ones).
The product of its digits is 16200000, while the sum is 53.
The spelling of 133155513652544 in words is "one hundred thirty-three trillion, one hundred fifty-five billion, five hundred thirteen million, six hundred fifty-two thousand, five hundred forty-four".
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