Base | Representation |
---|---|
bin | 1100000111000101101101… |
… | …0110111000011111110111 |
3 | 1202010222202011001121220101 |
4 | 3001301123112320133313 |
5 | 3221132011410432324 |
6 | 44153130541414531 |
7 | 2543021122612516 |
oct | 301613326703767 |
9 | 52128664047811 |
10 | 13315931342839 |
11 | 4274289108734 |
12 | 15b087256a447 |
13 | 7578c12819b8 |
14 | 3406ccd4667d |
15 | 1815a07c8944 |
hex | c1c5b5b87f7 |
13315931342839 has 2 divisors, whose sum is σ = 13315931342840. Its totient is φ = 13315931342838.
The previous prime is 13315931342837. The next prime is 13315931342849. The reversal of 13315931342839 is 93824313951331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13315931342839 - 21 = 13315931342837 is a prime.
Together with 13315931342837, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13315931342839.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13315931342837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657965671419 + 6657965671420.
It is an arithmetic number, because the mean of its divisors is an integer number (6657965671420).
Almost surely, 213315931342839 is an apocalyptic number.
13315931342839 is a deficient number, since it is larger than the sum of its proper divisors (1).
13315931342839 is an equidigital number, since it uses as much as digits as its factorization.
13315931342839 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6298560, while the sum is 55.
The spelling of 13315931342839 in words is "thirteen trillion, three hundred fifteen billion, nine hundred thirty-one million, three hundred forty-two thousand, eight hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •