Base | Representation |
---|---|
bin | 11110010010010101001101… |
… | …000001111101111000111000 |
3 | 122110121220100121002012111011 |
4 | 132102111031001331320320 |
5 | 114424331334424041440 |
6 | 1151143425133243304 |
7 | 40025314520206444 |
oct | 3622251501757070 |
9 | 573556317065434 |
10 | 133201113112120 |
11 | 39495302895779 |
12 | 12b33327333534 |
13 | 5942a70bc6181 |
14 | 24c6d7ad29824 |
15 | 105eceed379ea |
hex | 79254d07de38 |
133201113112120 has 16 divisors (see below), whose sum is σ = 299702504502360. Its totient is φ = 53280445244832.
The previous prime is 133201113112099. The next prime is 133201113112159. The reversal of 133201113112120 is 21211311102331.
It is a junction number, because it is equal to n+sod(n) for n = 133201113112091 and 133201113112100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1665013913862 + ... + 1665013913941.
Almost surely, 2133201113112120 is an apocalyptic number.
133201113112120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133201113112120 is an abundant number, since it is smaller than the sum of its proper divisors (166501391390240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133201113112120 is a wasteful number, since it uses less digits than its factorization.
133201113112120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3330027827814 (or 3330027827810 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 133201113112120 its reverse (21211311102331), we get a palindrome (154412424214451).
The spelling of 133201113112120 in words is "one hundred thirty-three trillion, two hundred one billion, one hundred thirteen million, one hundred twelve thousand, one hundred twenty".
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