Base | Representation |
---|---|
bin | 111110000001101101… |
… | …0011010010100000111 |
3 | 110201211000122011012022 |
4 | 1330003122122110013 |
5 | 4140244004210401 |
6 | 141105232513355 |
7 | 12423564604343 |
oct | 1740332322407 |
9 | 421730564168 |
10 | 133201241351 |
11 | 515436a0142 |
12 | 219949ab85b |
13 | c73a189399 |
14 | 66386d8623 |
15 | 36e8e0971b |
hex | 1f0369a507 |
133201241351 has 2 divisors, whose sum is σ = 133201241352. Its totient is φ = 133201241350.
The previous prime is 133201241323. The next prime is 133201241353. The reversal of 133201241351 is 153142102331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133201241351 - 214 = 133201224967 is a prime.
Together with 133201241353, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133201241351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133201241353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66600620675 + 66600620676.
It is an arithmetic number, because the mean of its divisors is an integer number (66600620676).
Almost surely, 2133201241351 is an apocalyptic number.
133201241351 is a deficient number, since it is larger than the sum of its proper divisors (1).
133201241351 is an equidigital number, since it uses as much as digits as its factorization.
133201241351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 133201241351 its reverse (153142102331), we get a palindrome (286343343682).
The spelling of 133201241351 in words is "one hundred thirty-three billion, two hundred one million, two hundred forty-one thousand, three hundred fifty-one".
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