1332301134040 has 16 divisors (see below), whose sum is σ = 2997677551680. Its totient is φ = 532920453600.

The previous prime is 1332301133983. The next prime is 1332301134041. The reversal of 1332301134040 is 404311032331.

It is a junction number, because it is equal to n+sod(n) for n = 1332301133996 and 1332301134014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332301134041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16653764136 + ... + 16653764215.

It is an arithmetic number, because the mean of its divisors is an integer number (187354846980).

Almost surely, 2^{1332301134040} is an apocalyptic number.

1332301134040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1332301134040 is an abundant number, since it is smaller than the sum of its proper divisors (1665376417640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1332301134040 is a wasteful number, since it uses less digits than its factorization.

1332301134040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33307528362 (or 33307528358 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1332301134040 its reverse (404311032331), we get a palindrome (1736612166371).

The spelling of 1332301134040 in words is "one trillion, three hundred thirty-two billion, three hundred one million, one hundred thirty-four thousand, forty".