Base | Representation |
---|---|
bin | 111110000010100100… |
… | …1010101100111101111 |
3 | 110201220001100111202102 |
4 | 1330011021111213233 |
5 | 4140323430220421 |
6 | 141112152045315 |
7 | 12424400015150 |
oct | 1740511254757 |
9 | 421801314672 |
10 | 133230320111 |
11 | 51559051479 |
12 | 219a269383b |
13 | c7431cac55 |
14 | 663c507927 |
15 | 36eb75060b |
hex | 1f052559ef |
133230320111 has 4 divisors (see below), whose sum is σ = 152263222992. Its totient is φ = 114197417232.
The previous prime is 133230320087. The next prime is 133230320129. The reversal of 133230320111 is 111023032331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111023032331 = 107 ⋅1037598433.
It is a cyclic number.
It is not a de Polignac number, because 133230320111 - 234 = 116050450927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133230320141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9516451430 + ... + 9516451443.
It is an arithmetic number, because the mean of its divisors is an integer number (38065805748).
Almost surely, 2133230320111 is an apocalyptic number.
133230320111 is a deficient number, since it is larger than the sum of its proper divisors (19032902881).
133230320111 is an equidigital number, since it uses as much as digits as its factorization.
133230320111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19032902880.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 133230320111 its reverse (111023032331), we get a palindrome (244253352442).
The spelling of 133230320111 in words is "one hundred thirty-three billion, two hundred thirty million, three hundred twenty thousand, one hundred eleven".
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