Base | Representation |
---|---|
bin | 111110000010100100… |
… | …1010101101000001101 |
3 | 110201220001100111210112 |
4 | 1330011021111220031 |
5 | 4140323430221031 |
6 | 141112152045405 |
7 | 12424400015222 |
oct | 1740511255015 |
9 | 421801314715 |
10 | 133230320141 |
11 | 515590514a6 |
12 | 219a2693865 |
13 | c7431cac79 |
14 | 663c507949 |
15 | 36eb75062b |
hex | 1f05255a0d |
133230320141 has 2 divisors, whose sum is σ = 133230320142. Its totient is φ = 133230320140.
The previous prime is 133230320137. The next prime is 133230320183. The reversal of 133230320141 is 141023032331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131367102916 + 1863217225 = 362446^2 + 43165^2 .
It is a cyclic number.
It is not a de Polignac number, because 133230320141 - 22 = 133230320137 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133230320341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66615160070 + 66615160071.
It is an arithmetic number, because the mean of its divisors is an integer number (66615160071).
Almost surely, 2133230320141 is an apocalyptic number.
It is an amenable number.
133230320141 is a deficient number, since it is larger than the sum of its proper divisors (1).
133230320141 is an equidigital number, since it uses as much as digits as its factorization.
133230320141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 133230320141 its reverse (141023032331), we get a palindrome (274253352472).
The spelling of 133230320141 in words is "one hundred thirty-three billion, two hundred thirty million, three hundred twenty thousand, one hundred forty-one".
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