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133231212312 = 2331117373172531
BaseRepresentation
bin111110000010100110…
…0101111011100011000
3110201220010000211121220
41330011030233130120
54140324142243222
6141112223132040
712424410422262
oct1740514573430
9421803024556
10133231212312
1151559600830
12219a2a44020
13c743451093
14663c69ab32
1536eb879b5c
hex1f0532f718

133231212312 has 256 divisors, whose sum is σ = 396533076480. Its totient is φ = 36840038400.

The previous prime is 133231212299. The next prime is 133231212403. The reversal of 133231212312 is 213212132331.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 52638487 + ... + 52641017.

It is an arithmetic number, because the mean of its divisors is an integer number (1548957330).

Almost surely, 2133231212312 is an apocalyptic number.

133231212312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133231212312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198266538240).

133231212312 is an abundant number, since it is smaller than the sum of its proper divisors (263301864168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133231212312 is a wasteful number, since it uses less digits than its factorization.

133231212312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2922 (or 2918 counting only the distinct ones).

The product of its digits is 1296, while the sum is 24.

Adding to 133231212312 its reverse (213212132331), we get a palindrome (346443344643).

It can be divided in two parts, 133231 and 212312, that added together give a palindrome (345543).

The spelling of 133231212312 in words is "one hundred thirty-three billion, two hundred thirty-one million, two hundred twelve thousand, three hundred twelve".