Base | Representation |
---|---|
bin | 11000110100010001… |
… | …10110110011010001 |
3 | 1021101112101102112220 |
4 | 30122020312303101 |
5 | 204241244243441 |
6 | 10042023211253 |
7 | 651111203340 |
oct | 143210666321 |
9 | 37345342486 |
10 | 13323431121 |
11 | 5717803000 |
12 | 26b9ba6b29 |
13 | 13443b4870 |
14 | 9056bbb57 |
15 | 52ea3d466 |
hex | 31a236cd1 |
13323431121 has 128 divisors (see below), whose sum is σ = 24723750912. Its totient is φ = 6209913600.
The previous prime is 13323431113. The next prime is 13323431159. The reversal of 13323431121 is 12113432331.
It is not a de Polignac number, because 13323431121 - 23 = 13323431113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13323431091 and 13323431100.
It is not an unprimeable number, because it can be changed into a prime (13323430121) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 13443936 + ... + 13444926.
It is an arithmetic number, because the mean of its divisors is an integer number (193154304).
Almost surely, 213323431121 is an apocalyptic number.
13323431121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13323431121 is a deficient number, since it is larger than the sum of its proper divisors (11400319791).
13323431121 is a wasteful number, since it uses less digits than its factorization.
13323431121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1084 (or 1062 counting only the distinct ones).
The product of its digits is 1296, while the sum is 24.
Adding to 13323431121 its reverse (12113432331), we get a palindrome (25436863452).
It can be divided in two parts, 13323 and 431121, that added together give a palindrome (444444).
The spelling of 13323431121 in words is "thirteen billion, three hundred twenty-three million, four hundred thirty-one thousand, one hundred twenty-one".
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