Base | Representation |
---|---|
bin | 111110000010110111… |
… | …1000100011100101100 |
3 | 110201220201222000211200 |
4 | 1330011233010130230 |
5 | 4140333443224434 |
6 | 141113144045500 |
7 | 12424550052240 |
oct | 1740557043454 |
9 | 421821860750 |
10 | 133240211244 |
11 | 51563697868 |
12 | 219a5a63890 |
13 | c7452820aa |
14 | 663d960420 |
15 | 36ec556199 |
hex | 1f05bc472c |
133240211244 has 72 divisors (see below), whose sum is σ = 385405832448. Its totient is φ = 38020203360.
The previous prime is 133240211213. The next prime is 133240211257. The reversal of 133240211244 is 442112042331.
133240211244 is a `hidden beast` number, since 1 + 3 + 3 + 2 + 402 + 11 + 244 = 666.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 137592 + ... + 534239.
It is an arithmetic number, because the mean of its divisors is an integer number (5352858784).
Almost surely, 2133240211244 is an apocalyptic number.
133240211244 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
133240211244 is an abundant number, since it is smaller than the sum of its proper divisors (252165621204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133240211244 is a wasteful number, since it uses less digits than its factorization.
133240211244 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 672635 (or 672630 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 133240211244 its reverse (442112042331), we get a palindrome (575352253575).
The spelling of 133240211244 in words is "one hundred thirty-three billion, two hundred forty million, two hundred eleven thousand, two hundred forty-four".
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