Base | Representation |
---|---|
bin | 1100000111100101010001… |
… | …0011110110000010111000 |
3 | 1202011210121120001110021012 |
4 | 3001321110103312002320 |
5 | 3221301334134243230 |
6 | 44201051331333052 |
7 | 2543441062061402 |
oct | 301712423660270 |
9 | 52153546043235 |
10 | 13324403040440 |
11 | 4277936171508 |
12 | 15b2437751188 |
13 | 75864144a80b |
14 | 340c94119b72 |
15 | 1818e93eb395 |
hex | c1e544f60b8 |
13324403040440 has 64 divisors (see below), whose sum is σ = 30138873811200. Its totient is φ = 5301539361792.
The previous prime is 13324403040409. The next prime is 13324403040511. The reversal of 13324403040440 is 4404030442331.
It is a junction number, because it is equal to n+sod(n) for n = 13324403040397 and 13324403040406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10354964 + ... + 11570396.
It is an arithmetic number, because the mean of its divisors is an integer number (470919903300).
Almost surely, 213324403040440 is an apocalyptic number.
13324403040440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13324403040440 is an abundant number, since it is smaller than the sum of its proper divisors (16814470770760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13324403040440 is a wasteful number, since it uses less digits than its factorization.
13324403040440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1216896 (or 1216892 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 13324403040440 its reverse (4404030442331), we get a palindrome (17728433482771).
The spelling of 13324403040440 in words is "thirteen trillion, three hundred twenty-four billion, four hundred three million, forty thousand, four hundred forty".
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