Base | Representation |
---|---|
bin | 11000110100011001… |
… | …10011100010000110 |
3 | 1021101121100000120020 |
4 | 30122030303202012 |
5 | 204242030410220 |
6 | 10042101320010 |
7 | 651123044361 |
oct | 143214634206 |
9 | 37347300506 |
10 | 13324466310 |
11 | 571834a831 |
12 | 26ba406006 |
13 | 1344687abc |
14 | 9058ab0d8 |
15 | 52eb95040 |
hex | 31a333886 |
13324466310 has 64 divisors (see below), whose sum is σ = 32248516608. Its totient is φ = 3523342464.
The previous prime is 13324466279. The next prime is 13324466317. The reversal of 13324466310 is 1366442331.
It is a super-3 number, since 3×133244663103 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13324466317) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1755684 + ... + 1763256.
It is an arithmetic number, because the mean of its divisors is an integer number (503883072).
Almost surely, 213324466310 is an apocalyptic number.
13324466310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13324466310 is an abundant number, since it is smaller than the sum of its proper divisors (18924050298).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13324466310 is a wasteful number, since it uses less digits than its factorization.
13324466310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8069.
The product of its (nonzero) digits is 31104, while the sum is 33.
The spelling of 13324466310 in words is "thirteen billion, three hundred twenty-four million, four hundred sixty-six thousand, three hundred ten".
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