Search a number
-
+
13325401133 = 111211400103
BaseRepresentation
bin11000110100100000…
…10111110000101101
31021101200002111220022
430122100113300231
5204242300314013
610042133331525
7651134016662
oct143220276055
937350074808
1013325401133
115718929110
1226ba796ba5
131344924455
14905a71a69
1552eccc008
hex31a417c2d

13325401133 has 4 divisors (see below), whose sum is σ = 14536801248. Its totient is φ = 12114001020.

The previous prime is 13325401127. The next prime is 13325401207. The reversal of 13325401133 is 33110452331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13325401133 - 214 = 13325384749 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13325401123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605700041 + ... + 605700062.

It is an arithmetic number, because the mean of its divisors is an integer number (3634200312).

Almost surely, 213325401133 is an apocalyptic number.

It is an amenable number.

13325401133 is a deficient number, since it is larger than the sum of its proper divisors (1211400115).

13325401133 is a wasteful number, since it uses less digits than its factorization.

13325401133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1211400114.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 13325401133 its reverse (33110452331), we get a palindrome (46435853464).

The spelling of 13325401133 in words is "thirteen billion, three hundred twenty-five million, four hundred one thousand, one hundred thirty-three".

Divisors: 1 11 1211400103 13325401133