Base | Representation |
---|---|
bin | 11000110101001100… |
… | …11111100000010011 |
3 | 1021102002000010110212 |
4 | 30122212133200103 |
5 | 204300241400034 |
6 | 10042501514335 |
7 | 651234221234 |
oct | 143246374023 |
9 | 37362003425 |
10 | 13331200019 |
11 | 5721129985 |
12 | 27007129ab |
13 | 1345ba4a47 |
14 | 90674108b |
15 | 5305752ce |
hex | 31a99f813 |
13331200019 has 2 divisors, whose sum is σ = 13331200020. Its totient is φ = 13331200018.
The previous prime is 13331200013. The next prime is 13331200021. The reversal of 13331200019 is 91000213331.
13331200019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13331200019 - 212 = 13331195923 is a prime.
It is a super-2 number, since 2×133312000192 (a number of 21 digits) contains 22 as substring.
Together with 13331200021, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13331199967 and 13331200003.
It is not a weakly prime, because it can be changed into another prime (13331200013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665600009 + 6665600010.
It is an arithmetic number, because the mean of its divisors is an integer number (6665600010).
Almost surely, 213331200019 is an apocalyptic number.
13331200019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331200019 is an equidigital number, since it uses as much as digits as its factorization.
13331200019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
The spelling of 13331200019 in words is "thirteen billion, three hundred thirty-one million, two hundred thousand, nineteen".
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