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13331200019 is a prime number
BaseRepresentation
bin11000110101001100…
…11111100000010011
31021102002000010110212
430122212133200103
5204300241400034
610042501514335
7651234221234
oct143246374023
937362003425
1013331200019
115721129985
1227007129ab
131345ba4a47
1490674108b
155305752ce
hex31a99f813

13331200019 has 2 divisors, whose sum is σ = 13331200020. Its totient is φ = 13331200018.

The previous prime is 13331200013. The next prime is 13331200021. The reversal of 13331200019 is 91000213331.

13331200019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13331200019 - 212 = 13331195923 is a prime.

It is a super-2 number, since 2×133312000192 (a number of 21 digits) contains 22 as substring.

Together with 13331200021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13331199967 and 13331200003.

It is not a weakly prime, because it can be changed into another prime (13331200013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665600009 + 6665600010.

It is an arithmetic number, because the mean of its divisors is an integer number (6665600010).

Almost surely, 213331200019 is an apocalyptic number.

13331200019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331200019 is an equidigital number, since it uses as much as digits as its factorization.

13331200019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

The spelling of 13331200019 in words is "thirteen billion, three hundred thirty-one million, two hundred thousand, nineteen".