Base | Representation |
---|---|
bin | 11000110101001101… |
… | …00010010011101100 |
3 | 1021102002000201020002 |
4 | 30122212202103230 |
5 | 204300242232000 |
6 | 10042502043432 |
7 | 651234266555 |
oct | 143246422354 |
9 | 37362021202 |
10 | 13331211500 |
11 | 5721137572 |
12 | 2700719578 |
13 | 1345baa039 |
14 | 90674532c |
15 | 5305788d5 |
hex | 31a9a24ec |
13331211500 has 96 divisors (see below), whose sum is σ = 29964235392. Its totient is φ = 5178240000.
The previous prime is 13331211479. The next prime is 13331211557. The reversal of 13331211500 is 511213331.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4775105 + ... + 4777895.
It is an arithmetic number, because the mean of its divisors is an integer number (312127452).
Almost surely, 213331211500 is an apocalyptic number.
13331211500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13331211500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14982117696).
13331211500 is an abundant number, since it is smaller than the sum of its proper divisors (16633023892).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13331211500 is a wasteful number, since it uses less digits than its factorization.
13331211500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3084 (or 3072 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 13331211500 its reverse (511213331), we get a palindrome (13842424831).
The spelling of 13331211500 in words is "thirteen billion, three hundred thirty-one million, two hundred eleven thousand, five hundred".
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