1333131201103 has 4 divisors (see below), whose sum is σ = 1435679755048. Its totient is φ = 1230582647160.

The previous prime is 1333131201049. The next prime is 1333131201119. The reversal of 1333131201103 is 3011021313331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1333131201103 - 2³³ = 1324541266511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1333131201173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51274276953 + ... + 51274276978.

It is an arithmetic number, because the mean of its divisors is an integer number (358919938762).

Almost surely, 2^{1333131201103} is an apocalyptic number.

1333131201103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1333131201103 is a deficient number, since it is larger than the sum of its proper divisors (102548553945).

1333131201103 is a wasteful number, since it uses less digits than its factorization.

1333131201103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102548553944.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1333131201103 its reverse (3011021313331), we get a palindrome (4344152514434).

The spelling of 1333131201103 in words is "one trillion, three hundred thirty-three billion, one hundred thirty-one million, two hundred one thousand, one hundred three".