Base | Representation |
---|---|
bin | 10011011001100100111… |
… | …011001111011100001100 |
3 | 11201110001100010222210012 |
4 | 103121210323033130030 |
5 | 133320224034104400 |
6 | 2500233301132352 |
7 | 165213165330635 |
oct | 23314473173414 |
9 | 4643040128705 |
10 | 1333133113100 |
11 | 474418984498 |
12 | 1964536ba0b8 |
13 | 9893860c4c9 |
14 | 48749b6a88c |
15 | 24a27b38d35 |
hex | 13664ecf70c |
1333133113100 has 72 divisors (see below), whose sum is σ = 2901504291840. Its totient is φ = 531668998720.
The previous prime is 1333133113073. The next prime is 1333133113183. The reversal of 1333133113100 is 13113313331.
It is a super-2 number, since 2×13331331131002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 56845577 + ... + 56869023.
It is an arithmetic number, because the mean of its divisors is an integer number (40298670720).
Almost surely, 21333133113100 is an apocalyptic number.
1333133113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1333133113100 is an abundant number, since it is smaller than the sum of its proper divisors (1568371178740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1333133113100 is a wasteful number, since it uses less digits than its factorization.
1333133113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25127 (or 25120 counting only the distinct ones).
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 1333133113100 its reverse (13113313331), we get a palindrome (1346246426431).
The spelling of 1333133113100 in words is "one trillion, three hundred thirty-three billion, one hundred thirty-three million, one hundred thirteen thousand, one hundred".
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