Base | Representation |
---|---|
bin | 10011011001100101101… |
… | …010101001011011001100 |
3 | 11201110002012112100200212 |
4 | 103121211222221123030 |
5 | 133320240224242200 |
6 | 2500234423341552 |
7 | 165213406056560 |
oct | 23314552513314 |
9 | 4643065470625 |
10 | 1333145540300 |
11 | 4744249a2202 |
12 | 1964578b18b8 |
13 | 9893b070a92 |
14 | 4874b6836a0 |
15 | 24a28c91035 |
hex | 13665aa96cc |
1333145540300 has 144 divisors (see below), whose sum is σ = 3501428894208. Its totient is φ = 430099891200.
The previous prime is 1333145540189. The next prime is 1333145540339. The reversal of 1333145540300 is 30455413331.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 76472585 + ... + 76490015.
It is an arithmetic number, because the mean of its divisors is an integer number (24315478432).
Almost surely, 21333145540300 is an apocalyptic number.
1333145540300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1333145540300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1750714447104).
1333145540300 is an abundant number, since it is smaller than the sum of its proper divisors (2168283353908).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1333145540300 is a wasteful number, since it uses less digits than its factorization.
1333145540300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23896 (or 23889 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 32.
The spelling of 1333145540300 in words is "one trillion, three hundred thirty-three billion, one hundred forty-five million, five hundred forty thousand, three hundred".
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