Base | Representation |
---|---|
bin | 1100001000000001101001… |
… | …1100010000010011010011 |
3 | 1202012112021112122211202212 |
4 | 3002000122130100103103 |
5 | 3221412440124214303 |
6 | 44204351342302335 |
7 | 2544130636034501 |
oct | 302003234202323 |
9 | 52175245584685 |
10 | 13332022101203 |
11 | 4280095a02643 |
12 | 15b3a032879ab |
13 | 759286a940b0 |
14 | 3413b7d81671 |
15 | 181be324aad8 |
hex | c201a7104d3 |
13332022101203 has 4 divisors (see below), whose sum is σ = 14357562262848. Its totient is φ = 12306481939560.
The previous prime is 13332022101197. The next prime is 13332022101227. The reversal of 13332022101203 is 30210122023331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13332022101203 - 210 = 13332022100179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13332022601203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512770080803 + ... + 512770080828.
It is an arithmetic number, because the mean of its divisors is an integer number (3589390565712).
Almost surely, 213332022101203 is an apocalyptic number.
13332022101203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13332022101203 is a deficient number, since it is larger than the sum of its proper divisors (1025540161645).
13332022101203 is a wasteful number, since it uses less digits than its factorization.
13332022101203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1025540161644.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13332022101203 its reverse (30210122023331), we get a palindrome (43542144124534).
The spelling of 13332022101203 in words is "thirteen trillion, three hundred thirty-two billion, twenty-two million, one hundred one thousand, two hundred three".
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