Base | Representation |
---|---|
bin | 11110010100000100111000… |
… | …101001101111100101000100 |
3 | 122111001100212211102121212212 |
4 | 132110010320221233211010 |
5 | 114433312432224131040 |
6 | 1151314500311002552 |
7 | 40040061262413131 |
oct | 3624047051574504 |
9 | 574040784377785 |
10 | 133321030302020 |
11 | 39531149a2a3a0 |
12 | 12b52613369458 |
13 | 5951171ba8082 |
14 | 24ccab5277588 |
15 | 1062ebc8d1d65 |
hex | 794138a6f944 |
133321030302020 has 24 divisors (see below), whose sum is σ = 305426360328768. Its totient is φ = 48480374655200.
The previous prime is 133321030302001. The next prime is 133321030302107. The reversal of 133321030302020 is 20203030123331.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 303002341376 + ... + 303002341815.
It is an arithmetic number, because the mean of its divisors is an integer number (12726098347032).
Almost surely, 2133321030302020 is an apocalyptic number.
133321030302020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133321030302020 is an abundant number, since it is smaller than the sum of its proper divisors (172105330026748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133321030302020 is a wasteful number, since it uses less digits than its factorization.
133321030302020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606004683211 (or 606004683209 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 133321030302020 its reverse (20203030123331), we get a palindrome (153524060425351).
The spelling of 133321030302020 in words is "one hundred thirty-three trillion, three hundred twenty-one billion, thirty million, three hundred two thousand, twenty".
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