Base | Representation |
---|---|
bin | 11110010100001111001000… |
… | …111101101111111011010100 |
3 | 122111002102022012202100201022 |
4 | 132110033020331233323110 |
5 | 114434003010044300040 |
6 | 1151323521053020312 |
7 | 40040631165250511 |
oct | 3624171075577324 |
9 | 574072265670638 |
10 | 133332041400020 |
11 | 3953588a458291 |
12 | 12b54786a84698 |
13 | 59522081b9c88 |
14 | 24cd43b7d6308 |
15 | 10634144146b5 |
hex | 7943c8f6fed4 |
133332041400020 has 48 divisors (see below), whose sum is σ = 287946425467008. Its totient is φ = 51837503902080.
The previous prime is 133332041400011. The next prime is 133332041400053. The reversal of 133332041400020 is 20004140233331.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 587666696 + ... + 587893535.
It is an arithmetic number, because the mean of its divisors is an integer number (5998883863896).
Almost surely, 2133332041400020 is an apocalyptic number.
133332041400020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133332041400020 is an abundant number, since it is smaller than the sum of its proper divisors (154614384066988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133332041400020 is a wasteful number, since it uses less digits than its factorization.
133332041400020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1175560400 (or 1175560398 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 133332041400020 its reverse (20004140233331), we get a palindrome (153336181633351).
The spelling of 133332041400020 in words is "one hundred thirty-three trillion, three hundred thirty-two billion, forty-one million, four hundred thousand, twenty".
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