Base | Representation |
---|---|
bin | 1100001000001001111000… |
… | …1111000101111011000011 |
3 | 1202012201222122022111112202 |
4 | 3002002132033011323003 |
5 | 3221432002202241311 |
6 | 44205355010543415 |
7 | 2544236505321140 |
oct | 302023617057303 |
9 | 52181878274482 |
10 | 13334233243331 |
11 | 4281020052430 |
12 | 15b431b897b6b |
13 | 759549bc7110 |
14 | 3415478bd3c7 |
15 | 181cc2418e3b |
hex | c209e3c5ec3 |
13334233243331 has 64 divisors (see below), whose sum is σ = 18861027655680. Its totient is φ = 9078819085440.
The previous prime is 13334233243277. The next prime is 13334233243381.
13334233243331 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13334233243331 - 238 = 13059355336387 is a prime.
It is a super-2 number, since 2×133342332433312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13334233243381) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22973606 + ... + 23546868.
It is an arithmetic number, because the mean of its divisors is an integer number (294703557120).
Almost surely, 213334233243331 is an apocalyptic number.
13334233243331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13334233243331 is a deficient number, since it is larger than the sum of its proper divisors (5526794412349).
13334233243331 is a wasteful number, since it uses less digits than its factorization.
13334233243331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 574536.
The product of its digits is 419904, while the sum is 38.
It can be divided in two parts, 1333423 and 3243331, that added together give a palindrome (4576754).
The spelling of 13334233243331 in words is "thirteen trillion, three hundred thirty-four billion, two hundred thirty-three million, two hundred forty-three thousand, three hundred thirty-one".
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