Base | Representation |
---|---|
bin | 10011011010011001001… |
… | …101110101110100101111 |
3 | 11201112022110220222212001 |
4 | 103122121031311310233 |
5 | 133324023130413033 |
6 | 2500500320353131 |
7 | 165244010225524 |
oct | 23323115656457 |
9 | 4645273828761 |
10 | 1334010404143 |
11 | 47482910620a |
12 | 1966594757a7 |
13 | 98a482b4731 |
14 | 487d049514b |
15 | 24a79b7be7d |
hex | 13699375d2f |
1334010404143 has 2 divisors, whose sum is σ = 1334010404144. Its totient is φ = 1334010404142.
The previous prime is 1334010404141. The next prime is 1334010404161. The reversal of 1334010404143 is 3414040104331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1334010404143 - 21 = 1334010404141 is a prime.
It is a super-3 number, since 3×13340104041433 (a number of 37 digits) contains 333 as substring.
Together with 1334010404141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334010404141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667005202071 + 667005202072.
It is an arithmetic number, because the mean of its divisors is an integer number (667005202072).
Almost surely, 21334010404143 is an apocalyptic number.
1334010404143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334010404143 is an equidigital number, since it uses as much as digits as its factorization.
1334010404143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1334010404143 its reverse (3414040104331), we get a palindrome (4748050508474).
The spelling of 1334010404143 in words is "one trillion, three hundred thirty-four billion, ten million, four hundred four thousand, one hundred forty-three".
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