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13340105 = 54362047
BaseRepresentation
bin110010111000…
…110111001001
3221002202011222
4302320313021
511403340410
61153531425
7221250302
oct62706711
927082158
1013340105
117591689
124573b75
1329c0c6c
141ab37a9
151287955
hexcb8dc9

13340105 has 8 divisors (see below), whose sum is σ = 16380672. Its totient is φ = 10423728.

The previous prime is 13340027. The next prime is 13340111. The reversal of 13340105 is 50104331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13340105 - 214 = 13323721 is a prime.

It is a super-2 number, since 2×133401052 = 355916802822050, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30809 + ... + 31238.

It is an arithmetic number, because the mean of its divisors is an integer number (2047584).

Almost surely, 213340105 is an apocalyptic number.

It is an amenable number.

13340105 is a deficient number, since it is larger than the sum of its proper divisors (3040567).

13340105 is an equidigital number, since it uses as much as digits as its factorization.

13340105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62095.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 13340105 is about 3652.4108476457. The cubic root of 13340105 is about 237.1663569983.

Adding to 13340105 its reverse (50104331), we get a palindrome (63444436).

The spelling of 13340105 in words is "thirteen million, three hundred forty thousand, one hundred five".

Divisors: 1 5 43 215 62047 310235 2668021 13340105