Base | Representation |
---|---|
bin | 1100001000100000010001… |
… | …1101011010100111100101 |
3 | 1202020022111111012001001111 |
4 | 3002020010131122213211 |
5 | 3222031304232211240 |
6 | 44212231222025021 |
7 | 2544541443420421 |
oct | 302100435324745 |
9 | 52208444161044 |
10 | 13340243241445 |
11 | 4283624591a1a |
12 | 15b5518578171 |
13 | 759c97083913 |
14 | 341957b71b81 |
15 | 182024d791ea |
hex | c220475a9e5 |
13340243241445 has 16 divisors (see below), whose sum is σ = 16704462297600. Its totient is φ = 10208089750144.
The previous prime is 13340243241397. The next prime is 13340243241469. The reversal of 13340243241445 is 54414234204331.
It is a cyclic number.
It is not a de Polignac number, because 13340243241445 - 27 = 13340243241317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13340243241398 and 13340243241407.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13173657 + ... + 14150113.
It is an arithmetic number, because the mean of its divisors is an integer number (1044028893600).
Almost surely, 213340243241445 is an apocalyptic number.
It is an amenable number.
13340243241445 is a deficient number, since it is larger than the sum of its proper divisors (3364219056155).
13340243241445 is a wasteful number, since it uses less digits than its factorization.
13340243241445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1095284.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 13340243241445 its reverse (54414234204331), we get a palindrome (67754477445776).
The spelling of 13340243241445 in words is "thirteen trillion, three hundred forty billion, two hundred forty-three million, two hundred forty-one thousand, four hundred forty-five".
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