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13341200232 = 2332324168841
BaseRepresentation
bin11000110110011001…
…01000111101101000
31021102202211012012010
430123030220331220
5204310321401412
610043500115520
7651415221333
oct143314507550
937382735163
1013341200232
11572683a218
122703b35ba0
131347c96729
14907bc561a
1553139d33c
hex31b328f68

13341200232 has 32 divisors (see below), whose sum is σ = 34803132480. Its totient is φ = 4253715840.

The previous prime is 13341200231. The next prime is 13341200233. The reversal of 13341200232 is 23200214331.

13341200232 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13341200231) and next prime (13341200233).

It is a junction number, because it is equal to n+sod(n) for n = 13341200199 and 13341200208.

It is not an unprimeable number, because it can be changed into a prime (13341200231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12083869 + ... + 12084972.

It is an arithmetic number, because the mean of its divisors is an integer number (1087597890).

Almost surely, 213341200232 is an apocalyptic number.

13341200232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13341200232 is an abundant number, since it is smaller than the sum of its proper divisors (21461932248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13341200232 is a wasteful number, since it uses less digits than its factorization.

13341200232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24168873 (or 24168869 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 13341200232 its reverse (23200214331), we get a palindrome (36541414563).

The spelling of 13341200232 in words is "thirteen billion, three hundred forty-one million, two hundred thousand, two hundred thirty-two".

Divisors: 1 2 3 4 6 8 12 23 24 46 69 92 138 184 276 552 24168841 48337682 72506523 96675364 145013046 193350728 290026092 555883343 580052184 1111766686 1667650029 2223533372 3335300058 4447066744 6670600116 13341200232