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133413005143 = 11237910166089
BaseRepresentation
bin111110001000000001…
…0001110011101010111
3110202100210002212111201
41330100002032131113
54141212212131033
6141142235413331
712432045555445
oct1742002163527
9422323085451
10133413005143
1151642188440
1221a338b4247
13c772001cc2
14665889db95
15370c7d947d
hex1f1008e757

133413005143 has 32 divisors (see below), whose sum is σ = 155316787200. Its totient is φ = 113407008000.

The previous prime is 133413005123. The next prime is 133413005171. The reversal of 133413005143 is 341500314331.

It is not a de Polignac number, because 133413005143 - 25 = 133413005111 is a prime.

It is a super-2 number, since 2×1334130051432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133413005123) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1985643 + ... + 2051731.

It is an arithmetic number, because the mean of its divisors is an integer number (4853649600).

Almost surely, 2133413005143 is an apocalyptic number.

133413005143 is a deficient number, since it is larger than the sum of its proper divisors (21903782057).

133413005143 is a wasteful number, since it uses less digits than its factorization.

133413005143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66303.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 133413005143 its reverse (341500314331), we get a palindrome (474913319474).

The spelling of 133413005143 in words is "one hundred thirty-three billion, four hundred thirteen million, five thousand, one hundred forty-three".

Divisors: 1 11 23 79 101 253 869 1111 1817 2323 7979 19987 25553 66089 87769 183517 726979 1520047 2018687 5221031 6674989 16720517 57431341 73424879 120083713 153524747 527324131 1320920843 1688772217 5800565441 12128455013 133413005143