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133413538301 is a prime number
BaseRepresentation
bin111110001000000010…
…0010000100111111101
3110202100211002221212022
41330100010100213331
54141212331211201
6141142255045525
712432053236031
oct1742004204775
9422324087768
10133413538301
1151642511a6a
1221a33b108a5
13c77215a894
14665899c1c1
15370c89241b
hex1f101109fd

133413538301 has 2 divisors, whose sum is σ = 133413538302. Its totient is φ = 133413538300.

The previous prime is 133413538267. The next prime is 133413538303. The reversal of 133413538301 is 103835314331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92315707225 + 41097831076 = 303835^2 + 202726^2 .

It is a cyclic number.

It is not a de Polignac number, because 133413538301 - 222 = 133409343997 is a prime.

Together with 133413538303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133413538303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706769150 + 66706769151.

It is an arithmetic number, because the mean of its divisors is an integer number (66706769151).

Almost surely, 2133413538301 is an apocalyptic number.

It is an amenable number.

133413538301 is a deficient number, since it is larger than the sum of its proper divisors (1).

133413538301 is an equidigital number, since it uses as much as digits as its factorization.

133413538301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 35.

The spelling of 133413538301 in words is "one hundred thirty-three billion, four hundred thirteen million, five hundred thirty-eight thousand, three hundred one".