Base | Representation |
---|---|
bin | 1100001000100111010110… |
… | …1100100010011011100111 |
3 | 1202020111101212222100102011 |
4 | 3002021311230202123213 |
5 | 3222044202103443030 |
6 | 44213143525055051 |
7 | 2544636512362501 |
oct | 302116554423347 |
9 | 52214355870364 |
10 | 13342143031015 |
11 | 4284409a03a47 |
12 | 15b5968857487 |
13 | 75a20a842766 |
14 | 341a981c2d71 |
15 | 1820d6a44b2a |
hex | c2275b226e7 |
13342143031015 has 8 divisors (see below), whose sum is σ = 16312657894848. Its totient is φ = 10472323586400.
The previous prime is 13342143030991. The next prime is 13342143031123. The reversal of 13342143031015 is 51013034124331.
13342143031015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13342143031015 - 219 = 13342142506727 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25173854511 + ... + 25173855040.
It is an arithmetic number, because the mean of its divisors is an integer number (2039082236856).
Almost surely, 213342143031015 is an apocalyptic number.
13342143031015 is a deficient number, since it is larger than the sum of its proper divisors (2970514863833).
13342143031015 is an equidigital number, since it uses as much as digits as its factorization.
13342143031015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50347709609.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 13342143031015 its reverse (51013034124331), we get a palindrome (64355177155346).
The spelling of 13342143031015 in words is "thirteen trillion, three hundred forty-two billion, one hundred forty-three million, thirty-one thousand, fifteen".
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