Base | Representation |
---|---|
bin | 11110010101101101001101… |
… | …000101101011101101110101 |
3 | 122111110002000010210201101110 |
4 | 132111231031011223231311 |
5 | 114442131332313221440 |
6 | 1151442143213145233 |
7 | 40051135115022003 |
oct | 3625551505535565 |
9 | 574402003721343 |
10 | 133433042320245 |
11 | 395746a9885588 |
12 | 12b70273a8b219 |
13 | 595b8b31996b5 |
14 | 24d429d763a73 |
15 | 1065d76463080 |
hex | 795b4d16bb75 |
133433042320245 has 64 divisors (see below), whose sum is σ = 218471583052800. Its totient is φ = 69525756518400.
The previous prime is 133433042320231. The next prime is 133433042320271. The reversal of 133433042320245 is 542023240334331.
It is not a de Polignac number, because 133433042320245 - 25 = 133433042320213 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 79647891 + ... + 81305919.
It is an arithmetic number, because the mean of its divisors is an integer number (3413618485200).
Almost surely, 2133433042320245 is an apocalyptic number.
133433042320245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133433042320245 is a deficient number, since it is larger than the sum of its proper divisors (85038540732555).
133433042320245 is a wasteful number, since it uses less digits than its factorization.
133433042320245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1658830.
The product of its (nonzero) digits is 622080, while the sum is 39.
Adding to 133433042320245 its reverse (542023240334331), we get a palindrome (675456282654576).
The spelling of 133433042320245 in words is "one hundred thirty-three trillion, four hundred thirty-three billion, forty-two million, three hundred twenty thousand, two hundred forty-five".
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