Base | Representation |
---|---|
bin | 1100001000111010111100… |
… | …0010010101101101001111 |
3 | 1202020222222020220210021112 |
4 | 3002032233002111231033 |
5 | 3222140433400432141 |
6 | 44215413320322235 |
7 | 2545214005116452 |
oct | 302165702255517 |
9 | 52228866823245 |
10 | 13347400014671 |
11 | 4286667384638 |
12 | 15b699531337b |
13 | 75a8679ba688 |
14 | 34203645b499 |
15 | 1822e330e7eb |
hex | c23af095b4f |
13347400014671 has 2 divisors, whose sum is σ = 13347400014672. Its totient is φ = 13347400014670.
The previous prime is 13347400014659. The next prime is 13347400014721. The reversal of 13347400014671 is 17641000474331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13347400014671 - 242 = 8949353503567 is a prime.
It is a super-2 number, since 2×133474000146712 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13347400014631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6673700007335 + 6673700007336.
It is an arithmetic number, because the mean of its divisors is an integer number (6673700007336).
Almost surely, 213347400014671 is an apocalyptic number.
13347400014671 is a deficient number, since it is larger than the sum of its proper divisors (1).
13347400014671 is an equidigital number, since it uses as much as digits as its factorization.
13347400014671 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 169344, while the sum is 41.
The spelling of 13347400014671 in words is "thirteen trillion, three hundred forty-seven billion, four hundred million, fourteen thousand, six hundred seventy-one".
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