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1334814949453 is a prime number
BaseRepresentation
bin10011011011001001001…
…010111100000001001101
311201121101112211010112111
4103123021022330001031
5133332200111340303
62501112220504021
7165302646602626
oct23331112740115
94647345733474
101334814949453
11475101270a97
121968429ab011
1398b45b9944b
1448869284a4d
1524ac5600b6d
hex136c92bc04d

1334814949453 has 2 divisors, whose sum is σ = 1334814949454. Its totient is φ = 1334814949452.

The previous prime is 1334814949451. The next prime is 1334814949469. The reversal of 1334814949453 is 3549494184331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1062511531524 + 272303417929 = 1030782^2 + 521827^2 .

It is a cyclic number.

It is not a de Polignac number, because 1334814949453 - 21 = 1334814949451 is a prime.

Together with 1334814949451, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1334814949451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667407474726 + 667407474727.

It is an arithmetic number, because the mean of its divisors is an integer number (667407474727).

Almost surely, 21334814949453 is an apocalyptic number.

It is an amenable number.

1334814949453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334814949453 is an equidigital number, since it uses as much as digits as its factorization.

1334814949453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 22394880, while the sum is 58.

The spelling of 1334814949453 in words is "one trillion, three hundred thirty-four billion, eight hundred fourteen million, nine hundred forty-nine thousand, four hundred fifty-three".