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133504031 is a prime number
BaseRepresentation
bin1111111010100…
…01110000011111
3100022012201002202
413331101300133
5233134112111
621125242115
73210523403
oct775216037
9308181082
10133504031
11693a5611
123886333b
132187468b
1413a33103
15bac1b3b
hex7f51c1f

133504031 has 2 divisors, whose sum is σ = 133504032. Its totient is φ = 133504030.

The previous prime is 133504001. The next prime is 133504037. The reversal of 133504031 is 130405331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133504031 - 26 = 133503967 is a prime.

It is a super-2 number, since 2×1335040312 = 35646652586497922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133503994 and 133504012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133504037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66752015 + 66752016.

It is an arithmetic number, because the mean of its divisors is an integer number (66752016).

Almost surely, 2133504031 is an apocalyptic number.

133504031 is a deficient number, since it is larger than the sum of its proper divisors (1).

133504031 is an equidigital number, since it uses as much as digits as its factorization.

133504031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 133504031 is about 11554.3944454047. The cubic root of 133504031 is about 511.0908740132.

Adding to 133504031 its reverse (130405331), we get a palindrome (263909362).

The spelling of 133504031 in words is "one hundred thirty-three million, five hundred four thousand, thirty-one".