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13351040404 = 2213256750777
BaseRepresentation
bin11000110111100100…
…01011010110010100
31021110110100010100221
430123302023112110
5204320331243104
610044451044124
7651564654022
oct143362132624
937413303327
1013351040404
115731350299
1227072a0644
13134a030610
14909227712
15532193c54
hex31bc8b594

13351040404 has 12 divisors (see below), whose sum is σ = 25161576244. Its totient is φ = 6162018624.

The previous prime is 13351040393. The next prime is 13351040407. The reversal of 13351040404 is 40404015331.

13351040404 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 3788156304 + 9562884100 = 61548^2 + 97790^2 .

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13351040407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128375337 + ... + 128375440.

Almost surely, 213351040404 is an apocalyptic number.

It is an amenable number.

13351040404 is a deficient number, since it is larger than the sum of its proper divisors (11810535840).

13351040404 is a wasteful number, since it uses less digits than its factorization.

13351040404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 256750794 (or 256750792 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13351040404 its reverse (40404015331), we get a palindrome (53755055735).

The spelling of 13351040404 in words is "thirteen billion, three hundred fifty-one million, forty thousand, four hundred four".

Divisors: 1 2 4 13 26 52 256750777 513501554 1027003108 3337760101 6675520202 13351040404