Base | Representation |
---|---|
bin | 11000110111100110… |
… | …01010110011111110 |
3 | 1021110110211022221120 |
4 | 30123303022303332 |
5 | 204320413102400 |
6 | 10044500411410 |
7 | 651600115623 |
oct | 143363126376 |
9 | 37413738846 |
10 | 13351300350 |
11 | 5731508623 |
12 | 27073a6b66 |
13 | 134a0c1a2b |
14 | 90929434a |
15 | 5321e5ca0 |
hex | 31bccacfe |
13351300350 has 24 divisors (see below), whose sum is σ = 33111225240. Its totient is φ = 3560346720.
The previous prime is 13351300349. The next prime is 13351300357. The reversal of 13351300350 is 5300315331.
It is a self number, because there is not a number n which added to its sum of digits gives 13351300350.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13351300357) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44504185 + ... + 44504484.
It is an arithmetic number, because the mean of its divisors is an integer number (1379634385).
Almost surely, 213351300350 is an apocalyptic number.
13351300350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13351300350 is an abundant number, since it is smaller than the sum of its proper divisors (19759924890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13351300350 is a wasteful number, since it uses less digits than its factorization.
13351300350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89008684 (or 89008679 counting only the distinct ones).
The product of its (nonzero) digits is 2025, while the sum is 24.
Adding to 13351300350 its reverse (5300315331), we get a palindrome (18651615681).
The spelling of 13351300350 in words is "thirteen billion, three hundred fifty-one million, three hundred thousand, three hundred fifty".
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