Base | Representation |
---|---|
bin | 1100001001001100000101… |
… | …1101101111001010011111 |
3 | 1202021102212010102022002221 |
4 | 3002103001131233022133 |
5 | 3222224401030412030 |
6 | 44221454231130211 |
7 | 2545436052502312 |
oct | 302230135571237 |
9 | 52242763368087 |
10 | 13352004154015 |
11 | 428860a29367a |
12 | 15b785b213967 |
13 | 75b11c826a97 |
14 | 342351b14979 |
15 | 1824b261de7a |
hex | c24c176f29f |
13352004154015 has 4 divisors (see below), whose sum is σ = 16022404984824. Its totient is φ = 10681603323208.
The previous prime is 13352004153967. The next prime is 13352004154033. The reversal of 13352004154015 is 51045140025331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13352004154015 - 227 = 13351869936287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335200415397 + ... + 1335200415406.
It is an arithmetic number, because the mean of its divisors is an integer number (4005601246206).
Almost surely, 213352004154015 is an apocalyptic number.
13352004154015 is a deficient number, since it is larger than the sum of its proper divisors (2670400830809).
13352004154015 is an equidigital number, since it uses as much as digits as its factorization.
13352004154015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2670400830808.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 13352004154015 its reverse (51045140025331), we get a palindrome (64397144179346).
The spelling of 13352004154015 in words is "thirteen trillion, three hundred fifty-two billion, four million, one hundred fifty-four thousand, fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •