1335225405335 has 4 divisors (see below), whose sum is σ = 1602270486408. Its totient is φ = 1068180324264.

The previous prime is 1335225405323. The next prime is 1335225405343. The reversal of 1335225405335 is 5335045225331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1335225405335 - 2⁶ = 1335225405271 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1335225405292 and 1335225405301.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133522540529 + ... + 133522540538.

It is an arithmetic number, because the mean of its divisors is an integer number (400567621602).

Almost surely, 2^{1335225405335} is an apocalyptic number.

1335225405335 is a deficient number, since it is larger than the sum of its proper divisors (267045081073).

1335225405335 is an equidigital number, since it uses as much as digits as its factorization.

1335225405335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267045081072.

The product of its (nonzero) digits is 810000, while the sum is 41.

The spelling of 1335225405335 in words is "one trillion, three hundred thirty-five billion, two hundred twenty-five million, four hundred five thousand, three hundred thirty-five".