Base | Representation |
---|---|
bin | 10011011011100010101… |
… | …111110110000000001101 |
3 | 11201122111110020221001112 |
4 | 103123202233312000031 |
5 | 133334034434221131 |
6 | 2501222550021405 |
7 | 165316410125105 |
oct | 23334257660015 |
9 | 4648443227045 |
10 | 1335244054541 |
11 | 475301505aa1 |
12 | 196942647865 |
13 | 98bb3a5b597 |
14 | 488aa264205 |
15 | 24aed11302b |
hex | 136e2bf600d |
1335244054541 has 4 divisors (see below), whose sum is σ = 1336064734752. Its totient is φ = 1334423374332.
The previous prime is 1335244054537. The next prime is 1335244054577. The reversal of 1335244054541 is 1454504425331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1335244054541 - 22 = 1335244054537 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1335244054741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410337665 + ... + 410340918.
It is an arithmetic number, because the mean of its divisors is an integer number (334016183688).
Almost surely, 21335244054541 is an apocalyptic number.
It is an amenable number.
1335244054541 is a deficient number, since it is larger than the sum of its proper divisors (820680211).
1335244054541 is an equidigital number, since it uses as much as digits as its factorization.
1335244054541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 820680210.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 1335244054541 its reverse (1454504425331), we get a palindrome (2789748479872).
The spelling of 1335244054541 in words is "one trillion, three hundred thirty-five billion, two hundred forty-four million, fifty-four thousand, five hundred forty-one".
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