Base | Representation |
---|---|
bin | 1100001001001111111101… |
… | …1101101100101001100000 |
3 | 1202021112112121200202211022 |
4 | 3002103333131230221200 |
5 | 3222234013322043404 |
6 | 44222145345505012 |
7 | 2545503613036502 |
oct | 302237735545140 |
9 | 52245477622738 |
10 | 13353044331104 |
11 | 4288aa3459065 |
12 | 15b7aab642168 |
13 | 75b25719029a |
14 | 34240dd1dd72 |
15 | 182523ad98be |
hex | c24ff76ca60 |
13353044331104 has 24 divisors (see below), whose sum is σ = 26293264395048. Its totient is φ = 6675389881600.
The previous prime is 13353044331101. The next prime is 13353044331127. The reversal of 13353044331104 is 40113344035331.
It is a super-3 number, since 3×133530443311043 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13353044331101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35192222 + ... + 35569629.
It is an arithmetic number, because the mean of its divisors is an integer number (1095552683127).
Almost surely, 213353044331104 is an apocalyptic number.
It is an amenable number.
13353044331104 is a deficient number, since it is larger than the sum of its proper divisors (12940220063944).
13353044331104 is an equidigital number, since it uses as much as digits as its factorization.
13353044331104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70767758 (or 70767750 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 13353044331104 its reverse (40113344035331), we get a palindrome (53466388366435).
The spelling of 13353044331104 in words is "thirteen trillion, three hundred fifty-three billion, forty-four million, three hundred thirty-one thousand, one hundred four".
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