Base | Representation |
---|---|
bin | 11000111000010100… |
… | …00010000110000001 |
3 | 1021110220002211121212 |
4 | 30130022002012001 |
5 | 204323431401303 |
6 | 10045233055505 |
7 | 652002060653 |
oct | 143412020601 |
9 | 37426084555 |
10 | 13357293953 |
11 | 5734931713 |
12 | 27093b7595 |
13 | 134b40cb43 |
14 | 909db46d3 |
15 | 5329cbad8 |
hex | 31c282181 |
13357293953 has 4 divisors (see below), whose sum is σ = 13938045888. Its totient is φ = 12776542020.
The previous prime is 13357293931. The next prime is 13357293977. The reversal of 13357293953 is 35939275331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13357293953 - 214 = 13357277569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13357293353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290375933 + ... + 290375978.
It is an arithmetic number, because the mean of its divisors is an integer number (3484511472).
Almost surely, 213357293953 is an apocalyptic number.
It is an amenable number.
13357293953 is a deficient number, since it is larger than the sum of its proper divisors (580751935).
13357293953 is an equidigital number, since it uses as much as digits as its factorization.
13357293953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 580751934.
The product of its digits is 2296350, while the sum is 50.
The spelling of 13357293953 in words is "thirteen billion, three hundred fifty-seven million, two hundred ninety-three thousand, nine hundred fifty-three".
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