Base | Representation |
---|---|
bin | 10011011100011111101… |
… | …100000101111011111111 |
3 | 11201202010201010121001020 |
4 | 103130133230011323333 |
5 | 133343133204401112 |
6 | 2501512232115223 |
7 | 165353633453334 |
oct | 23343754057377 |
9 | 4652121117036 |
10 | 1336266481407 |
11 | 475786657480 |
12 | 196b88b35b13 |
13 | 9901781b6b0 |
14 | 48965d6c98b |
15 | 24b5cc7448c |
hex | 1371fb05eff |
1336266481407 has 32 divisors (see below), whose sum is σ = 2216300486400. Its totient is φ = 703587448320.
The previous prime is 1336266481393. The next prime is 1336266481469. The reversal of 1336266481407 is 7041846626331.
It is not a de Polignac number, because 1336266481407 - 24 = 1336266481391 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 1336266481407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1336266483407) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 91605657 + ... + 91620242.
It is an arithmetic number, because the mean of its divisors is an integer number (69259390200).
Almost surely, 21336266481407 is an apocalyptic number.
1336266481407 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1336266481407 is a deficient number, since it is larger than the sum of its proper divisors (880034004993).
1336266481407 is a wasteful number, since it uses less digits than its factorization.
1336266481407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183225943.
The product of its (nonzero) digits is 3483648, while the sum is 51.
The spelling of 1336266481407 in words is "one trillion, three hundred thirty-six billion, two hundred sixty-six million, four hundred eighty-one thousand, four hundred seven".
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