Base | Representation |
---|---|
bin | 111110010011110000… |
… | …1001101100110001101 |
3 | 110210101020111002101122 |
4 | 1330213201031212031 |
5 | 4143014043112140 |
6 | 141245312250325 |
7 | 12444601524341 |
oct | 1744741154615 |
9 | 423336432348 |
10 | 133807004045 |
11 | 51824624670 |
12 | 21b238409a5 |
13 | c805821c50 |
14 | 6694d41621 |
15 | 37321b4ab5 |
hex | 1f2784d98d |
133807004045 has 16 divisors (see below), whose sum is σ = 188639805312. Its totient is φ = 89828477760.
The previous prime is 133807004041. The next prime is 133807004117. The reversal of 133807004045 is 540400708331.
It is not a de Polignac number, because 133807004045 - 22 = 133807004041 is a prime.
It is a super-3 number, since 3×1338070040453 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133807003996 and 133807004014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133807004041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93570617 + ... + 93572046.
It is an arithmetic number, because the mean of its divisors is an integer number (11789987832).
Almost surely, 2133807004045 is an apocalyptic number.
It is an amenable number.
133807004045 is a deficient number, since it is larger than the sum of its proper divisors (54832801267).
133807004045 is a wasteful number, since it uses less digits than its factorization.
133807004045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187142692.
The product of its (nonzero) digits is 40320, while the sum is 35.
The spelling of 133807004045 in words is "one hundred thirty-three billion, eight hundred seven million, four thousand, forty-five".
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